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周一分享(八十九):Matlab精读复刻论文之代码复刻8

Matlab精读复刻论文

Matlab reads the reproduction paper

分享兴趣,传播快乐,

增长见闻,留下美好。

亲爱的您,

这里是LearingYard学苑!

今天小编为大家带来Matlab精读复刻论文。

欢迎您的用心访问!

本期推文阅读时长大约5分钟,请您耐心阅读。

Share interests, spread happiness,

increase knowledge, and leave beauty behind.

Dear you,

this is LearningYard Academy!

Today,the editor brings you Matlab intensive reading reproduction paper.

Welcome your visit!

The reading time of this tweet is about 5 minutes, please read it with patience.

本周小编将从思维导图、精读内容、知识补充三个板块介绍两个子群的复杂网络划分。

This week, the editor will introduce the complex network division of the two subgroups from three sections: mind map, intensive reading content, and knowledge supplementation.

01

思维导图

02

精读内容

上周可得D1、D5、D6、D7、D9、D11、D12、D13、D14、D17、D19为一组,D2、D3、D4、D8、D10、D15、D16、D18、D20为一组。

Last week,we obtained D1, D5, D6, D7, D9, D11, D12, D13, D14, D17, D19 are a group, and D2, D3, D4, D8, D10, D15, D16, D18, D20 are a group.

本周将在两组的基础上,按照前几周的操作对两个子群的复杂网络继续进行划分。

This week, the complex network of the two subgroups will continue to be divided on the basis of the two groups, as has been done in previous weeks.

对第一组进行划分,代码如下图所示:

Divide the first group, the code is shown in the following figure:

结果如下图所示:

The result is shown in the following figure:

1、5、6、7、9、11、12、13、14、17、19中第1、3、5、7、9、11个数为一组。即1、6、9、12、14、19为一组。第2、4、6、8、10个数为一组,即5、7、11、13、17为一组。使用节点替代行元素得到D1、D6、 D9、D12、 D13、D14、D19为一组。D5、 D7、D11、 D13、D17为一组。

The numbers 1, 3, 5, 5, 7, 9, 11, 12, 13, 14, 17, 19 are a group of 1, 3, 5, 7, 9, and 11. That is, 1, 6, 9, 12, 14, 19 as a group. The 2nd, 4th, 6th, 8th, and 10th numbers are a group, that is, 5, 7, 11, 13, and 17 are a group. Use nodes instead of row elements to get D1, D6, D9, D12, D13, D14, D19 as a group. D5, D7, D11, D13, D17are a group.

对第二组进行划分,代码如下图所示:

Divide the second group, the code is shown in the following figure:

结果如下图所示:

The result is shown in the following figure:

2、3、4、8、10、15、16、18、20中第1、5、6、7、9个数是一组,即2、 10、15、16、20为一组。第2、3、4、8个数是一组,即3、4、8、18为一组。使用节点替代行元素得到D2、 D10、D15、D16为一组。D3、D4、D8、D18、 D20为一组。

The numbers 1, 5, 6, 7, and 9 in 2, 3, 4, 8, 10, 15, 16, 18, and 20 are a group, that is, 2, 10, 15, 16, and 20 are a group. The numbers 2, 3, 4, and 8 are a group, that is, 3, 4, 8, and 18 are a group. Use nodes instead of row elements to get D2, D10, D15, D16 as a group. D3, D4, D8, D18, D20are a group.

03

知识补充

上述步骤是用CONCOR法进行聚类分析。聚类分析指将物理或抽象对象的集合分组为由类似的对象组成的多个类的分析过程。根据在数据中发现的描述对象及其关系的信息,将数据对象分组。目的是,组内的对象相互之间是相似的(相关的),而不同组中的对象是不同的(不相关的)。

The above step is to perform cluster analysis using the CONCOR method. Clustering refers to the process of grouping a collection of physical or abstract objects into multiple classes composed of similar objects. Group data objects based on information found in the data that describes objects and their relationships. The purpose is that objects within a group are similar (related) to each other, while objects in different groups are different (unrelated).

聚类与分类的差异:

Differences between clustering and classification:

今天的分享就到这里了。

如果您对今天的文章有独特的想法,

欢迎给我们留言,

让我们相约明天。

祝您今天过得开心快乐!

That's it for today's sharing.

If you have a unique idea about today’s article,

welcome to leave us a message,

let us meet tomorrow.

I wish you a nice day today!

参考资料:Bing Microsoft Translator、百度、CSDN

参考文献:

[1]王伟明, 徐海燕, 朱建军. 复杂网络视角下的大规模群体DEMATEL决策方法 [J]. 系统工程理论与实践, 2021, 41(1): 200-212.

本文由LearningYard学苑原创,如有侵权请在后台留言!

文字|Zheng

排版|Zheng

审核|任务达人

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